Chase and Oliver go to the movie theater and purchase refreshments for their friends.

Chase spends a total of $40.50 on 9 drinks and 4 bags of popcorn.

Oliver spends a total of $38.25 on 3 drinks and 5 bags of popcorn.

Write a system of equations that can be used to find the price of one drink and the price of one bag of popcorn.

Using these equations, determine and state the price of a bag of popcorn, to the nearest cent.

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Answer:

[tex]\left\{\begin{array}{l}9x+4y=40.50\\ \\3x+5y=38.25\end{array}\right.[/tex]

The price of one bag of popcorn is $1.20

Step-by-step explanation:

Let x be the price of one drink and y be the price of one bag of popcorn.

Chase:

He spends a total of $40.50 on 9 drinks which cost $9x and on 4 bags of popcorn which cost $4y. Hence,

[tex]9x+4y=40.50[/tex]

Oliver:

He spends a total of $38.25 on 3 drinks which cost $3x and on 5 bags of popcorn which cost $5y. Then

[tex]3x+5y=38.25[/tex]

Write a system of two equations:

[tex]\left\{\begin{array}{l}9x+4y=40.50\\ \\3x+5y=38.25\end{array}\right.[/tex]

To solve this system of two equations, multiply the second equation by 3

[tex]\left\{\begin{array}{l}9x+4y=40.50\\ \\9x+15y=114.75\end{array}\right.[/tex]

and subtract the first equation from the secoond:

[tex](9x+15y)-(9x+5y)=114.75-40.50\\ \\9x+15y-9x-5y=74.25\\ \\10y=74.25\\ \\y=7.425[/tex]

Substitute [tex]y=7.425[/tex] into the first equation:

[tex]9x+4\cdot 7.425=40.50\\ \\9x+29.7=40.50\\ \\9x=40.50-29.7\\ \\9x=10.8\\ \\x=1.2[/tex]

The price of one bag of popcorn is $1.20