Answer:
The minimum uncertainty in the speed of a bacterium is [tex]5.27\times 10^{-29}\ m/s.[/tex]
Explanation:
We know by Heisenberg Uncertainty principal :
[tex]\Delta p\times \Delta x=\dfrac{h}{4\pi}\\\\m\Delta v\times \Delta x=\dfrac{h}{4\pi}\\\\\Delta v\times \Delta x=\dfrac{h}{4\pi m}[/tex] ....equation 1.
Putting value of [tex]\Delta x[/tex], m ,h in above equation we get :
[tex]\Delta v\times 10^{-6}\ m=\dfrac{6.626\times 10^{-34}}{4\times \dfrac{22}{7}}\\\\\Delta v=\dfrac{6.626\times 10^{-34}}{4\times \dfrac{22}{7}\times 10^{-6}}=5.27\times 10^{-29}\ m/s.[/tex]
Hence, this is the required solution.
