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Suppose that we have a fuse box containing 20 fuses, of which 5 are defective. If 2 fuses are selected at random and removed from the box in succession without replacing the first, what is the probability that both fuses are defective?

Respuesta :

Answer:

Unlikely

Step-by-step explanation:

Because that leaves 15 lives fuses

amna04352

Answer:

0.0526 (3 sf)

Step-by-step explanation:

(5/20)×(4/19)

= 0.0526315789

= 0.0526 (3 sf)

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