Answer:
V=6q/20πεor= 3q/10πεor
Step-by-step explanation:
distance between the charges is r-r/6 since the charges are located at the surface and r/6. V=w/q and W =Force X distance =kQq/r
and V = Kq/r also k =1/4πεo. Hence the potential at location A inside the ball to the charge +q at the surface is 3q/10πεor