The diffraction phenomenon can be observed whenever the wavelength is comparable in magnitude to the size of the slit opening. To be "diffracted," how fast must a person weighing 84 kg move through a door 1 m wide

Respuesta :

Answer:

Velocity,[tex]v=7.89\times10^{-36}m/s[/tex]

Explanation:

Diffraction will only occur when the wavelength,[tex]\lambda[/tex], is comparable in size to the slit opening. Given the,[tex]\lambda=1m,[/tex],and mass of the person as [tex]84kg[/tex], we can apply

De-Broglie equation, to obtain the velocity.

[tex]\lambda=\frac{h}{mv}\\v=\frac{6.626\times10^{-34}Js}{84kg\times1m}\\v=7.89\times10^{-36}m/s[/tex]

The velocity of the person is [tex]7.89\times10^{-36}m/s[/tex]