Assuming that a chemical reaction doubles in rate for each 10° temperature increase, by what factor would the rate increase if the temperature were increased 40°C?

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Answer:

It'll be increased by a factor of 16...

Explanation:

After 10 C = Doubles

After 20 C = 4 Times

After 30 C = 8 Times

After 40 C = 16 Times

(The rate of reaction doubles as per 10 C rise in temperature as calculated)

When the chemical reaction doubles in rate for each 10° temperature increase, the rate when increased to 40°C will be 16.

Note that  for every 10° temperature, the rate is said to doubles (2)

and for  40°C, the double rate will be multiplied. So it will be:

2 x 2 x 2 x 2 = 16

Why does the rate of reaction increases?

A catalyst is known to be a factor that increases the rate of concentration of a reactant in any given solution.

It is known to be the one that boast the the surface area of a solid reactant, and so still increases the temperature as well as the rate of a reaction.

Therefore, the rate as at 40°C temperature  will be 16 from the solution given above.

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