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2. A portion of the body receives 0.15 mGy from radiation with a quality factor Q = 6 and 0.22 mGy from radiation with Q = 10. (a) What is the total dose? (b) What is the total dose equivalent?

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Answer with Explanation:

We are given that

[tex]D_1=0.15mGy[/tex]

[tex]D_2=0.22mGy[/tex]

[tex]Q_1=6[/tex]

[tex]Q_2=10[/tex]

a.We have to find the total dose

Total dose=[tex]D=D_1+D_2[/tex]

Using the formula then, we get

[tex]D=0.15+0.22[/tex]

[tex]D=0.37mGy[/tex]

b.We have to find the total dose equivalent

Total dose equivalent=H=[tex]D_1Q_1+D_2Q_2[/tex]

Using the formula

[tex]H=0.15(6)+0.22(10)[/tex]

H=3.1mSv

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