Answer:
It is the same.
Explanation:
- Assuming no friction between the object and the surface, and no other external force acting on the object, than gravity and normal force, we can say the following:
[tex]\Delta K + \Delta U = 0[/tex]
- where ΔK = change in kinetic energy, and ΔU = change in gravitational potential energy.
- As ΔU = -m*g*h (being h the height of the plane), it will be the same for both inclined planes, as we are told that they have the same height.
- If the object starts from rest, the change in kinetic energy will be as follows:
[tex]\Delta K = K_{f} - K_{0} = \frac{1}{2} * m*v_{f} ^{2} (1)[/tex]
[tex]\Delta K = -\Delta U = m*g*h (2)[/tex]
- From (1) and (2) we see that the mass m and the height h are the same, the speed at the bottom of inclined plane A, will be the same as the one at the bottom of inclined plane B.
