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Find the magnitude of the torque produced by a 4.5 N force applied to a door at a perpendicular distance of 0.26 m from the hinge. Answer in units of N · m.

Respuesta :

Answer:

The required torque is 1.17 N-m.

Explanation:

The given data :-

The magnitude of force ( F ) = 4.5 N.

The length of arm ( r ) = 0.26 m.

Here given that force is applied at perpendicular means ( ∅ ) = 90°.

The torque ( T ) is given by

T = F * r * sin∅

T = 4.5 * 0.26 * sin 90°

T = 4.5 * 0.26 * 1

T = 1.17 N-m.

nuhulawal20

The magnitude of the torque produced by the given force perpendicular to the lever is 1.17N.m.

Given the data in the question;

  • Force; [tex]F = 4.5N[/tex]
  • Perpendicular distance or radius; [tex]r = 0.26m[/tex]
  • Since the force is perpendicular to the lever, Angle; [tex]\theta = 90^o[/tex]

Torque; [tex]T = \ ?[/tex]

Torque simply the measure of the force that can cause an object to rotate about an axis. It is expressed as:

[tex]T = rFsin\theta[/tex]

Where r is radius, F is force applied and θ is the angle between the force and the lever arm.

We substitute our given values into the equation;

[tex]T = 0.26m * 4.5N * sin90^o\\\\T = 0.26m * 4.5N * 1\\\\T = 1.17N.m[/tex]

Therefore, the magnitude of the torque produced by the given force perpendicular to the lever is 1.17N.m.

Learn more: https://brainly.com/question/12794319

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