Answer:
What mass (g) of barium iodide is contained in 188 mL of a barium iodide solution that has an iodide ion concentration of 0.532 M?
A) 19.6
B) 39.1
C) 19,600
D) 39,100
E) 276
The correct answer to the question is
B) 39.1 grams
Explanation:
To solve the question
The molarity ratio is given by
188 ml of 0.532 M solution of iodide.
Therefore we have number of moles = 0.188 × 0.532 M = 0.100016 Moles
To find the mass, we note that the Number of moles = [tex]\frac{Mass}{Molar Mass}[/tex] from which we have
Mass = Number of moles × molar mass
Where the molar mass of Barium Iodide = 391.136 g/mol
= 0.100016 moles ×391.136 g/mol = 39.12 g
According to the question,
The number of moles will be:
= [tex]0.188\times 0.532[/tex]
= [tex]0.100016 \ Moles[/tex]
We know the molar mass of Barium iodide = 391.136 g/mol
Now,
→ [tex]Number \ of \ moles = \frac{Mass}{Molar \ mass}[/tex]
or,
→ [tex]Mass = Number \ of \ moles\times Molar \ mass[/tex]
By substituting the values, we get
[tex]= 0.100016\times 391.136[/tex]
[tex]= 39.12 \ g[/tex]
Thus the above answer is right.
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