Answer:
[tex]\boxed{\text{36 $\mu$mol}}[/tex]
Explanation:
Data:
c = 1.5 x 10⁻⁴ mol/L
V = 240.0 mL
Calculations:
[tex]\text{Moles} = \text{0.2400 L} \times \dfrac{1.5 \times 10^{-4}\text{ mol}}{\text{1 L}} \times \dfrac{10^{6}\text{ $\mu$mol}}{\text{1 mol}} = \textbf{36 $\mu$mol}\\\\\text{The chemist has added $\boxed{\textbf{36 $\mu$mol}}$ of magnesium fluoride to the flask.}[/tex]
