Answer:
The answer to the question is
The star’s approximate radial velocity is 68.52 km/s
Explanation:
To solve the
The formula is
[tex]\frac{\lambda-\lambda_{rw}}{\lambda_{rw}} = \frac{v_r}{c}[/tex] where
[tex]v_r[/tex] = velocity of the star
λ = Star's spectrum wavelength = 656.45 nm
[tex]\lambda_{rw}[/tex] = Rest wavelength = 656.30 nm
c = Speed of light = 299 792 458 m / s
Therefore we have
[tex]\frac{656.45-656.30}{656.30} =\frac{v_r}{299 792 458}[/tex] or [tex]v_r[/tex] = 68518.7699 m/s or 68.52 km/s