Answer:
The balanced chemical equation for this process:
[tex]H_2SO_4(aq)+Ca(OH)_2(s)\rightarrow 2H_2O(l)+CaSO_4(aq)[/tex]
$194.51 is the cost that the firm will incur from this use of slaked lime.
Explanation:
The balanced chemical equation for this process
[tex]H_2SO_4(aq)+Ca(OH)_2(s)\rightarrow 2H_2O(l)+CaSO_4(aq)[/tex]
Moles of sulfuric acid = n
Volume of sulfuric acid disposed = V = 1200 gallons = 3.785 × 1200 L = 4,542 L
1 gallon = 3.785 Liter
Morality of the sulfuric acid = M = 1.05 m
[tex]Molarity(M)=\frac{n}{V(L)}[/tex]
[tex]n=m\times V=1.05 M\times 4,542 L=4,769.1 mol[/tex]
According to reaction, 1 mol of sulfuric acid reacts with 1 mole of calcium hydroxide.Then 4,769.1 moles of sulfuric acid will recat with ;
[tex]\frac{1}{1}\times 4,769.1 mol=4,769.1 mol[/tex] of calcium hydroxide
Mass of 4,769.1 moles of calcium hydroxide:
4,769.1 mol 74 g/mol = 352,913.4 g
= [tex]\frac{352,913.4 }{453.6} pounds =778.03 pounds[/tex]
(1 pound = 453.6 grams)
Cost of 1 pound of slaked lime = $0.25
Cost of 778.03 pounds of slaked lime = $0.25 × 778.03 = $194.51
$194.51 is the cost that the firm will incur from this use of slaked lime.