Answer:
1. 2C2H6 + 7O2 —> 4CO2 + 6H2O
2. 56moles of O2
Explanation:
Ethane undergo Combustion to produce CO2 and H20 according the equation below:
C2H6 + O2 —> CO2 + H2O
Let us balance the equation. There are 6 atoms of H on the left side and 2 atoms on the right side. It can be balanced by putting 3 in front of H2O as shown below:
C2H6 + O2 —> CO2 + 3H2O
There are 2 atoms of C on left and 1atom on the right. It can be balanced by putting 2 in front of CO2 as shown below:
C2H6 + O2 —> 2CO2 + 3H2O
There are a total of 7 atoms of O on the right and 2 atoms on the left. It can be balanced by putting 7/2 in front of O2 as shown below:
C2H6 + 7/2O2 —> 2CO2 + 3H2O
Now we multiply through by 2 to remove the fraction as shown below
2C2H6 + 7O2 —> 4CO2 + 6H2O
Now the equation is balanced
2. 2C2H6 + 7O2 —> 4CO2 + 6H2O
From the equation above,
2 moles of ethane(C2H6) combined with 7moles of O2.
Therefore, 16moles of ethane(C2H6) will combine with = (16x7)/2 = 56moles of O2