Speed is 231 ft/s.
Distance is 4620 ft.
Solution:
First we have to convert the unit of speed from m/s to ft/ s.
Then for 20 seconds, we have to calculate the feet covered by the parachute.
[tex]1 meter $=3.3$ feet\\\\$\frac{70 \frac{m}{s} \times 3.3 f t}{1 m}=231 \frac{f t}{s}$[/tex]
In 20 seconds, the parachute covers the distance of,
[tex]231 \frac{f t}{s} \times 20 s=4620 \mathrm {ft}[/tex]
