Answer:
mass = 25.03 g
Explanation:
Given data:
Initial temperature = 67.5°C
Final temperature = 25.2°C
Heat released = -4425 j
Mass of water = ?
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 25.2°C - 67.5°C
ΔT = -42.3°C
Specific heat of water = 4.18 j/g.°C
Q = m.c. ΔT
-4425 j = m × 4.18 j/g.°C × -42.3°C
-4425 j = m × -176.81 j/g
m = -4425 j / -176.81 j/g
m = 25.03 g
