Respuesta :
Answer:
0.108mol of Hydrogen
Explanation:
The formula for the compound is: CH3COOH
From the formula of the compound,
There are 2moles of oxygen and 4moles of Hydrogen.
If for every 2moles of oxygen, 4moles of Hydrogen is present.
Then, for 0.054 moles of oxygen = (0.054 x 4)/2 = 0.108mol of Hydrogen is present
Answer:
For 0.027 moles CH3COOH we have 0.108 moles H ≈ 1.1 *10^-1 moles H
Explanation:
Step 1: Data given
Acetic acid = CH3COOH
Number of moles oxygen in the sample = 0.054 moles
Step 2: calculate moles CH3COOH
In 1 mol CH3COOH we have 2 moles O
For 0.054 moles Oxygen we have 0.054/2 = 0.027 moles CH3COOH
Step 3: Calculate moles H
In 1 mol CH3COOH we have 4 moles H
For 0.027 moles CH3COOH we have 4*0.027 = 0.108 moles H ≈ 1.1 *10^-1 moles