Answer:
0.050 m
Explanation:
The strength of the magnetic field produced by a current-carrying wire is given by
[tex]B=\frac{\mu_0 I}{2\pi r}[/tex]
where
[tex]\mu_0=4\pi \cdot 10^{-7} H/m[/tex] is the vacuum permeability
I is the current in the wire
r is the distance from the wire
And the magnetic field around the wire forms concentric circles, and it is tangential to the circles.
In this problem, we have:
[tex]I=1.41 A[/tex] (current in the wire)
[tex]B=5.61\mu T=5.61\cdot 10^{-6} T[/tex] (strength of magnetic field)
Solving for r, we find the distance from the wire:
[tex]r=\frac{\mu_0 I}{2\pi B}=\frac{(4\pi \cdot 10^{-7})(1.41)}{2\pi (5.61\cdot 10^{-6})}=0.050 m[/tex]
