Amount of ice-cream in the cone = 6.3 in³
Solution:
Given data:
Diameter of the cone = 2 in
Radius of the cone = 2 ÷ 2 = 1 in
Height of the cone = 6 in
The value of π = 3.14
Volume of the cone = [tex]\frac{1}{3} \pi r^2 h[/tex]
[tex]$=\frac{1}{3}\times 3.14\times 1^2\times 6[/tex]
= 6.3
Volume of the cone = 6.3 in³
Amount of ice-cream in the cone = 6.3 in³
