Answer:
The distance is 709.5 m.
Explanation:
Given that,
Speed = 150 m/s
Distance = 110 m
Suppose, How far short of the target should it drop the package?
We need to calculate the time
Using equation of motion
[tex]s=ut+\dfrac{1}{2}gt^2[/tex]
[tex]t^2=\dfrac{2s}{g}[/tex]
Where, g = acceleration due to gravity
t = time
Put the value into the formula
[tex]t=\sqrt{\dfrac{2\times110}{9.8}}[/tex]
[tex]t=4.73\ sec[/tex]
We need to calculate the distance
Using formula of distance
[tex]d= vt[/tex]
Put the value into the formula
[tex]d=150\times4.73[/tex]
[tex]d=709.5\ m[/tex]
Hence, The distance is 709.5 m.