Step-by-step explanation:
Diameter of circle = 25 m
Therefore, radius of the circle = 12.5 m
[tex]area \: of \: bottom \: of \: pool \\ = \pi {r}^{2} \\ = 3.14 \times ( {12.5)}^{2} \\ = 3.14 \times 156.25 \\ = 490.625 \: {m}^{2} \\ \approx490.63 \: {m}^{2} [/tex]