Answer:
Option C. [tex](x+3)^2=13[/tex]
Step-by-step explanation:
we have
[tex]x^2+6x-4=0[/tex]
Group terms that contain the same variable, and move the constant to the opposite side of the equation
[tex]x^2+6x=4[/tex]
Complete the square. Remember to balance the equation by adding the same constants to each side
[tex]x^2+6x+3^2=4+3^2[/tex]
[tex]x^2+6x+9=13[/tex]
Rewrite as perfect squares
[tex](x+3)^2=13[/tex]
