Ammonium phosphate ((NH4)3PO4) is an important ingredient in many fertilizers. It can be made by reacting phosphoric acid (H3PO4) with ammonia (NH3).
What mass of ammonium phosphate is produced by the reaction of 4.9 g phosphoric acid?

Respuesta :

Answer:

7.46 g

Explanation:

Equation for the reaction can be represented as:

[tex]3NH_3 +H_3PO_4 -----------> [{(NH_4)_3PO_4][/tex]

1 mole of phosphoric acid is equivalent to 1 mole of ammonium phosphate in the above reaction; and as such;

numbers of moles of phosphoric acid = numbers of moles of ammonium phosphate

Given that the mass of phosphoric acid = 4.9 g; we can determine the number of moles of phosphoric acid in the process.

[tex]number of moles = \frac{mass}{molarmass}[/tex]

mass = 4.9 g

molar mass = 98 g/mol

numbers of moles = [tex]\frac{4.9}{98}[/tex]

= 0.05 mole

Therefore, the mass of ammonium phosphate can be determine:

mass = number of moles × molar mass

mass of  ammonium phosphate = 0.05 mole  ×  149.09 g/mol

mass of  ammonium phosphate = 7.4545 g

mass of  ammonium phosphate ≅ 7.46 g