A 111.6 g sample of iron was heated from 0°C to 20°C. It absorbed 1004 J of energy. What is the specific heat capacity of iron? A 0.00578 J/g°C B 0.45 J/g°C C 2.20 J/g°C D 4.18 J/g°C

Respuesta :

Answer:

b.

[tex]0.45J/g\textdegree C[/tex]

Explanation:

Specific heat capacity is the amount of heat required to raise one gram of substance by one degree celcius.

It's calculated by the formula:[tex]s=\frac{q}{m\bigtriangleup T}[/tex], where q=heat and m= mass

[tex]\bigtriangleup T=20-0=20\textdegree C\\q=1004J\\m=111.6g[/tex]

Therefore:

[tex]s=\frac{1004J}{111.6g\times20\textdegree C}\\=0.45J/g\textdegree C[/tex]

Hence the iron's specific heat capacity is [tex]0.45J/g\textdegree C[/tex]