Respuesta :
Answer:
The bucket was the dropped from 56 th floor.
Explanation:
Given that,
Height of floor = 4.9 m
Height of 14 floor = 68.6 m
Time taken = 1 sec
We need to calculate the speed of the bucket
Using equation of motion
[tex]s=ut+\dfrac{1}{2}gt^2[/tex]
Put the value into the formula
[tex]68.6=v\times1+\dfrac{1}{2}\times9.8\times(1)^2[/tex]
[tex]v=68.6-\dfrac{1}{2}\times9.8\times(1)^2[/tex]
[tex]v=63.7\ m/s[/tex]
We need to calculate the time
Using equation of motion
[tex]v=u+gt[/tex]
[tex]t=\dfrac{v}{g}[/tex]
Put the value into the formula
[tex]t=\dfrac{63.7}{9.8}[/tex]
[tex]t=6.5\ sec[/tex]
We need to calculate the distance
Using equation of motion
[tex]s=ut+\dfrac{1}{2}gt^2[/tex]
[tex]s=0+\dfrac{1}{2}gt^2[/tex]
Put the value into the formula
[tex]s=\dfrac{1}{2}\times9.8\times(6.5)^2[/tex]
[tex]s=207.025\ m[/tex]
We need to calculate the number of floor
[tex]n=\dfrac{s}{h_{f}}[/tex]
Put the value into the formula
[tex]n=\dfrac{207.025}{4.9}[/tex]
[tex]n=42.25\approx42[/tex]
The bucket was the dropped from
[tex]f=14+42= 56[/tex]
Hence, The bucket was the dropped from 56 th floor.
