Answer:102.84 N
Explanation:
Given
Mass of board [tex]m=12.8\ kg[/tex]
Length of board [tex]l=6.1\ m[/tex]
First support is at one end and second support is at a distance of 2.38 m from the other end
Suppose [tex]R_1[/tex] and [tex]R_2[/tex] are the reactions at the two support
Taking moment about the first end we can write
[tex]mg\times \dfrac{6.1}{2}-R_2(6.1-2.38)=0[/tex]
[tex]R_2=\dfrac{12.8\times 9.8 \times 3.05}{3.72}[/tex]
[tex]R_2=102.84\ N[/tex]
