Answer:
Cyclic butanol , 1 cyclopropyl methanol, 1-methyl cyclo propan-1-ol.
Explanation:
IR wave-number of O-H bond = [tex]3600 - 3200 cm^{-1}[/tex]
The intensity of the signal is broad and strong.
IR wave number of C=C bond = [tex]1680 - 1600 cm^{-1}[/tex]
The intensity of the signal is weak.But for the given chemical formula it didn't show any signal in its IR spectrum.This means that no unsaturation is present.
IR wave number of C=O bond = [tex]1780 - 1650 cm^{-1}[/tex]
The intensity of the signal is broad and strong.But for the given chemical formula it didn't show any signal in its IR spectrum. This means that no C=O is present in the compound
For the given formula the possible structures wil be:
[tex]C_4H_8O: C_4H_7OH[/tex]
As we know from the I.R. data that no unsaturation is present which indicates that the given compound has cyclic structure.
The possible structures are attached in an image.
