Respuesta :

Answer:

6.928 lb.ft

Step-by-step explanation:

|PQ| = 6 in

= 0.5 ft

|F| = 16 lb

Torque = |PQ × F|

= |PQ| × |F| sin θ

= 0.5 × 16 × sin 60

= 4 × sqrt(3)

= 6.928 lb.ft.