Respuesta :
Answer:
0.467 Hz
Explanation:
Wave properties are related thus
v = fλ
v = velocity of the wave = ?
f = 0.30 Hz
λ = wavelength = 30 m
v = 0.3×30 = 9.0 m/s
But if the boat is now moving at 5.0 m/s in the direction of the oncoming wave,
The speed of the wave relative to the boat = 9 - (-5) = 14.0 m/s
f = (v/λ) = (14/30) = 0.467 Hz
Hope this helps!
Answer:
The answer to the question is;
The boat’s vertical oscillation frequency if you drive the boat at 5.0 m/s in the direction of the oncoming waves moving at 9 m/s in the opposite direction is 0.467 Hz.
Explanation:
We note the frequency of the water wave = 0.3 Hz
Distance between crests or wavelength of water wave = 30 m
Speed v of a wave is given by Frequency f × Wavelength λ
Therefore the speed of the wave = f·λ = 0.3 × 30 = 9 m/s
(b) Distance between crests = 30 m = wavelength λ
Boat speed = 5.0 m/s v
Speed of the wave with respect to the boat = 5 + 9 = 14 m/s
From the wave speed relationship, we have
v = fλ f = [tex]\frac{v}{\lambda}[/tex] =[tex]\frac{14}{30} = \frac{7}{15}[/tex] = 0.467 Hz which is high.
