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Determine the following: A. P(X > 654) for N(650, 10) B. P(Z < 0.72) Solution: A. 1 – pnorm(654,650,10) = 0.3445783 B. qnorm(0.72) = 0.5828415 What was done wrong in this solution?

Respuesta :

Answer:

a) We have the following distribution [tex] X \sim N(\mu =650, \sigma =10)[/tex]

And we want to calculate:

[tex] P(X>654) [/tex]

And in order to calclate this in the ti 84 we can use the following code

2nd> Vars>DISTR

And then we need to use the following code:

1-normalcdf(-1000,654,650,10)

And we got:

[tex] P(X>654)=0.3445783 [/tex]

b) For this case we assume a normal standard distribution and we want to calculate:

[tex] P(z<0.72)[/tex]

And using the following code in the Ti84 or using the normal standard table we got:

normalcdf(-1000,0.72,0,1)

[tex] P(z<0.72)=0.76424[/tex]

So this part was the wrong solution from the solution posted,

Step-by-step explanation:

Part a

We have the following distribution [tex] X \sim N(\mu =650, \sigma =10)[/tex]

And we want to calculate:

[tex] P(X>654) [/tex]

And in order to calclate this in the ti 84 we can use the following code

2nd> Vars>DISTR

And then we need to use the following code:

1-normalcdf(-1000,654,650,10)

And we got:

[tex] P(X>654)=0.3445783 [/tex]

Part b

For this case we assume a normal standard distribution and we want to calculate:

[tex] P(z<0.72)[/tex]

And using the following code in the Ti84 or using the normal standard table we got:

normalcdf(-1000,0.72,0,1)

[tex] P(z<0.72)=0.76424[/tex]

So this part was the wrong solution from the solution posted,

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