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A little girl is going on the merry-go-round for the first time, and wants her 51 kg mother to stand next to her on the ride, 2.7 m from the merry-go-round's center. Part A If her mother's speed is 5.0 m/s when the ride is in motion, what is her angular momentum around the center of the merry-go-round

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Olajidey

Answer:

686.70 kg m² / s

Explanation:

L= m * r²

= 51 * 2.7²

= 371.79 kg m²

w = v/r

= 5.0 m/s / 2.7 m

= 1.85 rev/sec

The momentum = I * w

= 371.79 * 1.85

= 686.70 kg m² / s

The angular momentum around the center of the merry-go-round is 686.70 kg m² / s

Calculation of the angular momentum:

Since her mother who is 51  kg stand next to her on the ride, 2.7 m from the merry-go-round's center. And, the mother speed is 5.0 m/s.

So, the following formulas should be applied

L= m * r²

= 51 * 2.7²

= 371.79 kg m²

Now

w = v/r

= 5.0 m/s / 2.7 m

= 1.85 rev/sec

So finally

The momentum = I * w

= 371.79 * 1.85

= 686.70 kg m² / s

learn more about momentum here; https://brainly.com/question/24717686

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