A man can swim at 4 ft/s in still water. He wishes to cross tje 40-ft wide river to point B, 30 ft downstream. If the river flows with a velocity of 2 ft/s, determine the speed of the man and the time needed to make the crossing. Note While in the water he must not direct himself toward point B to reach the point.

Respuesta :

Answer:

[tex]v \approx 4.472\,\frac{ft}{s}[/tex], [tex]t = 10\,s[/tex]

Explanation:

Since man and river report constant speeds and velocities are mutually perpendicullar, the absolute speed of the man is calculated by the Pythagorean Theorem:

[tex]v = \sqrt{(4\,\frac{ft}{s} )^{2}+(2\,\frac{ft}{s} )^{2}}[/tex]

[tex]v \approx 4.472\,\frac{ft}{s}[/tex]

The required time to make the crossing is:

[tex]t = \frac{40\,ft}{4\,\frac{ft}{s} }[/tex]

[tex]t = 10\,s[/tex]