Given a integer, convert to String, using String Builder class. No error checking needed on input integer, However do read in the input integer using Scanner API. This program requires you to use a loop.

Question

contestada

Respuesta :

DayyanKhan DayyanKhan · Answer 1 · 2020-03-05T09:36:06+01:00

Answer:

The program in Java will be:

// Java program to demonstrate working parseInt()

public class GFG

{

public static void main(String args[])

{

int decimalExample = Integer.parseInt("20");

int signedPositiveExample = Integer.parseInt("+20");

int signedNegativeExample = Integer.parseInt("-20");

int radixExample = Integer.parseInt("20",16);

int stringExample = Integer.parseInt("geeks",29);

// Uncomment the following code to check

// NumberFormatException

// String invalidArguments = "";

// int emptyString = Integer.parseInt(invalidArguments);

// int outOfRangeOfInteger = Integer.parseInt("geeksforgeeks",29);

// int domainOfNumberSystem = Integer.parseInt("geeks",28);

System.out.println(decimalExample);

System.out.println(signedPositiveExample);

System.out.println(signedNegativeExample);

System.out.println(radixExample);

System.out.println(stringExample);

}