Answer:
Given the equation:
[tex]y =x^2+2x+7[/tex] and [tex]y=x+7[/tex]
Equate these two equation we get;
[tex]x^2+2x+7 = x+7[/tex]
Subtract 7 from both sides we get;
[tex]x^2+2x= x[/tex]
Subtract x from both sides we get;
[tex]x^2+x= 0[/tex]
or
[tex]x(x+1)=0[/tex]
⇒x = 0 and x +1=0
⇒x = 0 and x = -1
Now, find the values of y:
For x = 0
y=x+7
y = 0+7 = 7
⇒(0, 7)
For x = -1
y=x+7
y = -1+7 =6
⇒(-1, 6)
Therefore, the solution set for the given equations are: (0, 7) and (-1, 6)
