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H(x)= 8 1 ​ x 3 −x 2 h, left parenthesis, x, right parenthesis, equals, start fraction, 1, divided by, 8, end fraction, x, cubed, minus, x, squared What is the average rate of change of h hh over the interval − 2 ≤ x ≤ 2 −2≤x≤2minus, 2, is less than or equal to, x, is less than or equal to, 2?

Respuesta :

xero099

Answer:

[tex]m = 324[/tex]

Step-by-step explanation:

The average rate of change is:

[tex]m = \frac{h(2)-h(-2)}{2 - (-2)}[/tex]

[tex]h(-2) = 81\cdot (-2)^{3}-(-2)^{2}[/tex]

[tex]h(-2) = -652[/tex]

[tex]h(2) = 81\cdot (2)^{3}-(2)^{2}[/tex]

[tex]h(2) = 644[/tex]

[tex]m = \frac{644-(-652)}{2-(-2)}[/tex]

[tex]m = 324[/tex]

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