Answer:
(a) 4.27 x 10^-4 Telsa
(b) 3.28 x 10^-4 Telsa
Explanation:
side of square, a = 5.49 cm
inner radius, r = 18.1 cm = 0.181 m
number of turns,N = 450
current, i = 0.859 A
(a)
The magnetic field due to a solenoid due to inner radius is
[tex]B = \frac{\mu_{0}Ni}{2\pi r_{inner}}[/tex]
[tex]B = \frac{4\pi\times 10^{-7}\times 450\times 0.859}{2\pi \times 0.181}[/tex]
B = 4.27 x 10^-4 Telsa
(b)
The outer radius is R = 18.1 + 5.49 = 23.59 cm = 0.236 m
The magnetic field due to the outer radius is
[tex]B = \frac{\mu_{0}Ni}{2\pi r_{outer}}[/tex]
[tex]B = \frac{4\pi\times 10^{-7}\times 450\times 0.859}{2\pi \times 0.236}[/tex]
B = 3.28 x 10^-4 Tesla
