Respuesta :
Answer: Thus volume of hydrogen is 48.7 L and volume of CO is 24.4 L
Explanation:
The balanced chemical reaction is :
[tex]CO+2H_2\rightarrow CH_3OH[/tex]
To calculate the moles :
[tex]\text{Moles }=\frac{\text{given mass}}\times{\text{Molar Mass}}[/tex]
[tex]\text{Moles of} CH_3OH=\frac{25.8g}{32g/mol}=0.81moles[/tex]
According to stoichiometry :
1 mole of [tex]CH_3OH[/tex] require = 2 moles of [tex]H_2[/tex]
Thus 0.81 moles of [tex]CH_3OH[/tex] will require=[tex]\frac{2}{1}\times 0.81=1.62moles[/tex] of [tex]H_2[/tex]
To find Volume of hydrogen :
According to ideal gas equation :
[tex]PV=nRT[/tex]
P= pressure of gas = 748 mm Hg = 0.98 atm (760mmHg=1atm)
R = Gas constant = [tex]0.0821\text{ L atm }mol^{-1}K^{-1}[/tex]
T = temperature of the gas = [tex]86^0C=(273+86)K=359K[/tex]
V = volume of gas = ?
n = number of moles = 1.62
[tex]0.98\times V=1.62\times 0.0821\times 359[/tex]
[tex]V=48.7L[/tex]
According to stoichiometry :
2 moles of [tex]H_2[/tex] require = 1 moles of [tex]CH_3OH[/tex]
Thus 1.62 moles of [tex]H_2[/tex] will require=[tex]\frac{1}{2}\times 1.62=0.81moles[/tex] of [tex]CO[/tex]
To find Volume of CO:
[tex]0.98\times V=0.81\times 0.0821\times 359[/tex]
[tex]V=24.4L[/tex]
Thus volume of hydrogen is 48.7 L and volume of CO is 24.4 L
