Answer:
[tex]\eta_{th} = 26.8\,\%[/tex]
Explanation:
The maximum theoretical efficiency for a heat engine is given by the Carnot's Cycle. The temperatures of the hot reservoir and the cold reservoir at 1.0 atmosphere are 373.15 K and 273.15 K, respectively. Then:
[tex]\eta_{th} = \left(1 - \frac{T_{L}}{T_{H}} \right)\times 100\,\%[/tex]
[tex]\eta_{th} = \left(1-\frac{273.15\,K}{373.15\,K} \right)\times 100\,\%[/tex]
[tex]\eta_{th} = 26.8\,\%[/tex]
