Find the area of △ABC with side lengths b = 6 and c = 17, and included angle A = 135∘. Round your answer to the nearest tenth.

Respuesta :

Answer:

[tex]A=36.1\ units^2[/tex]

Step-by-step explanation:

we know that

The area of a triangle applying the law of sines is given by the formula

[tex]A=\frac{1}{2}(b)(c)sin(A)[/tex]

where

A is the included angle between the sides b and c

substitute the given values

[tex]A=\frac{1}{2}(6)(17)sin(135^o)=36.1\ units^2[/tex]