Answer:
The elevation to the top of the building from the point on the ground where the shopper is standing is = 17.35°
Step-by-step explanation:
From the ΔABC
AB = height of the building = 250 feet
BC = 800 ft
Angle of elevation = [tex]\theta[/tex]
[tex]\tan \theta = \frac{AB}{BC}[/tex]
[tex]\tan \theta = \frac{250}{800}[/tex]
[tex]\tan \theta[/tex] = 0.3125
[tex]\theta = 17.35[/tex]°
Therefore the elevation to the top of the building from the point on the ground where the shopper is standing is = 17.35°
