Answer:
0.25M
Explanation:
We can apply the following formula to find molarity ,since the Molarity (M) is the number of moles of solute per liter of solution.
[tex]Molarity=\frac{mol}{L}[/tex]
[tex]mol=0.50mol[/tex] of KI(potassium iodide)
[tex]L=2.0liters[/tex]
we can substitute the values to find the molarity
[tex]Molarity=\frac{mol}{L}\\Molarity=\frac{0.50mol}{2.0liters} \\Molarity=0.25M[/tex]
So the molarity of 2.0 liters of an aqueous solution that contains 0.50 mol of potassium iodide is 0.25M
Answer:
[tex]0.25moldm^{-3}[/tex]
Explanation:
Molarity could be defined as the amount of solute (in moles) dissolved in 1 litre of water to give its solution. It can also be referred to as the concentration of the resulting solution.
The molarity is thus calculated as follows;
[tex]1litre=1dm^{-3}\\hence\\2litres=2dm^{-3}[/tex]
[tex]molarity=\frac{0.5mole}{2dm^{3}}\\molarity=0.25moldm^{-3}[/tex]
