Given the magnitude of two vectors |⃗| = 4 and |⃗⃗| = 6, and |⃗ + ⃗⃗| = 8. Find the angle between the vectors ⃗ and ⃗⃗(when they are placed tail to tail). = ∠(⃗, ⃗⃗)

Respuesta :

Answer:

the angle between the vectors [tex]\overrightarrow{a}[/tex] and [tex]\overrightarrow{b}[/tex]  is  [tex]cos\phi = \frac{1}{6}[/tex]

Step-by-step explanation:

Given -

[tex]|\overrightarrow{a}| = 4[/tex] , [tex]|\overrightarrow{b}| = 6[/tex] ,  [tex]|\overrightarrow{a} + \overrightarrow{b} | = 8[/tex]

If two vector [tex]\overrightarrow{a}[/tex] and [tex]\overrightarrow{b}[/tex] are inclined at an angle [tex]\phi[/tex]

vector parallelogram method

[tex]|\overrightarrow{a} + \overrightarrow{b} |^{2} = |\overrightarrow{a}|^{2} + |\overrightarrow{b}|^{2} + 2 |\overrightarrow{a}||\overrightarrow{b}|cos\phi[/tex]

64 = 16 + 36 + 48 [tex]cos\phi[/tex]

[tex]cos\phi = \frac{1}{6}[/tex]