Question is incomplete. Complete question has been attached.
Answer:
0.91
Explanation:
According to Hard-Weinberg equilibrium, allele frequency in a population remains constant in absence of an evolutionary force. Hardy-Weinberg equilibrium equation for two alleles is as follows:
p + q = 1
where,
p = frequency of dominant allele
q = frequency of recessive allele
Here,
q = 0.09
So, p = 1-q
= 1 - 0.09
= 0.91
Hence, frequency of dominant allele = 0.91
