Answer:
Airplane plane should take off at angle of elevation of 1.43°.
Step-by-step explanation:
As given in the figure attached,
Distance of the building from the point of take off (BC) = 3000 ft
Height of the building (AB) = 75 feet
We have to calculate angle of elevation (θ) so that airplane doesn't hit the building.
tanθ = [tex]\frac{\text{Opposite side}}{\text{Adjacent side}}[/tex]
tanθ = [tex]\frac{AB}{BC}[/tex]
tanθ = [tex]\frac{75}{3000}[/tex]
θ = [tex]tan^{-1}(0.025)[/tex]
θ = 1.432° ≈ 1.43°
Therefore, airplane should take off at angle of elevation of 1.43° to avoid the accident.
