Answer: The new volume of the gas is 0.11 L
Explanation:
To calculate the volume when temperature and pressure has changed, we use the equation given by combined gas law.
The equation follows:
[tex]\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}[/tex]
where,
[tex]P_1,V_1\text{ and }T_1[/tex] are the initial pressure, volume and temperature of the gas
[tex]P_2,V_2\text{ and }T_2[/tex] are the final pressure, volume and temperature of the gas
At STP:
The temperature at this condition is taken as 273 K and the pressure at this condition is taken as 1 atm or 101.3 kPa.
We are given:
[tex]P_1=101.3kPa\\V_1=0.2L\\T_1=273K\\P_2=202.6kPa\\V_2=?\\T_2=300K[/tex]
Putting values in above equation, we get:
[tex]\frac{101.3kPa\times 0.2L}{273K}=\frac{202.6kPa\times V_2}{300K}\\\\V_2=\frac{101.3\times 0.2\times 300}{273\times 202.6}=0.11L[/tex]
Hence, the new volume of the gas is 0.11 L
