At a temperature of -33 degree Celsius, a sample of gas exerts a pressure of 53.3 kPa. At what temperature will the pressure reach 133 kPa?

Respuesta :

Answer: The final temperature of the gas is 325.8°C

Explanation:

To calculate the final temperature of the system, we use the equation given by Gay-Lussac Law. This law states that pressure of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

[tex]\frac{P_1}{T_1}=\frac{P_2}{T_2}[/tex]

where,

[tex]P_1\text{ and }T_1[/tex] are the initial pressure and temperature of the gas.

[tex]P_2\text{ and }T_2[/tex] are the final pressure and temperature of the gas.

We are given:

[tex]P_1=53.3kPa\\T_1=-33^oC=[-33+273]K=240K\\P_2=133kPa\\T_2=?[/tex]

Putting values in above equation, we get:

[tex]\frac{53.3kPa}{240K}=\frac{133kPa}{T_2}\\\\T_2=\frac{133\times 240}{53.3}=598.9K[/tex]

Converting the temperature from kelvins to degree Celsius, by using the conversion factor:

[tex]T(K)=T(^oC)+273[/tex]

[tex]598.9=T(^oC)+273\\\\T(^oC)=325.8^oC[/tex]

Hence, the final temperature of the gas is 325.8°C