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A car has a unibody-type frame and is supported by four suspension springs, each with a force constant of 47100 N/m. The combined mass of the car’s frame and everything inside it (the engine, the seats, the passengers, etc.) is 1190 kg. Because of worn-out shockabsorbers, the car vibrates up and down every time it is driven over a pothole. What is the frequency of this vibration? Answer in units of Hz.

Respuesta :

Answer:

Frequency = 2Hz

Explanation:

In simple harmonic motion,

Frequency is given by the formula;

f = (1/2π)√(k/m))

Where,

k is spring constant and

m is mass

Now, the question says there are 4 suspension springs with each having a spring constant of 47100 N/m. Thus, the total amount of spring constant will be;

K_total = 4 x 47100 N/m = 188,400 N/m

Thus, let's now find the frequency since we have m = 1190kg

f = (1/2π)√(k/m)

f = (1/2π)√(188400/1190)

f = (1/2π) x 12.5825

f = 0.159149 x 12.5825 = 2 Hz

jayilych4real

The frequency of this vibration is 2Hz

What is Frequency?

This refers to the rate per second of vibration in a wave.

Hence, to show the steps used to find the frequency of this vibration:

Frequency is given by the formula

f = (1/2π)√(k/m))

Where,

  • k is spring constant
  • m is mass

Hence, the questions says that there are four suspension rings with a spring constant of 47100 N/m, so, the total amount of spring constant will be:

K_total = 4 x 47100 N/m = 188,400 N/m

Since we now have the mass, we can find the frequency

  • f = (1/2π)√(k/m)
  • f = (1/2π)√(188400/1190)
  • f = (1/2π) x 12.5825
  • f = 0.159149 x 12.5825 = 2 Hz

Read more about frequency here:

https://brainly.com/question/10728818

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