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A cell membrane is 0,0000005 m thick and has an electric potential difference between its surfaces of 0,10 V. What is the electric field within the membrane?

Respuesta :

Answer:

Electric field in the membrane is given as

[tex]E = 2 \times 10^5 V/m[/tex]

Explanation:

As we know that electric field in a region is related to its potential difference given by the formula

[tex]E = \frac{\Delta V}{\Delta x}[/tex]

here we know that

[tex]\Delta V = 0.10 V[/tex]

[tex]\Delta x = 0.0000005 m[/tex]

so we have

[tex]E = \frac{0.10}{0.0000005}[/tex]

[tex]E = 2 \times 10^5 V/m[/tex]

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