Answer:
Step-by-step explanation:
We will evaluate that with n values starting at 1 and ending at 5. To do that, simply replace the exponent n with 1, then 2, then 3, then 4, then 5.
[tex]f(1)=(\frac{2}{3})^1[/tex] so
[tex]f(1)=\frac{2}{3}[/tex]
Then f(2):
[tex]f(2)=(\frac{2}{3})^2[/tex] simplifies a bit so maybe it's easier to see how to handle this:
[tex]f(2)=(\frac{2^2}{3^2})[/tex] so
[tex]f(2)=\frac{4}{9}[/tex]
Then f(3):
[tex]f(3)=(\frac{2^3}{3^3})=\frac{8}{27}[/tex]
And f(4):
[tex]f(4)=(\frac{2^4}{3^4})=\frac{16}{81}[/tex]
And finally, f(5):
[tex]f(5)=(\frac{2^5}{3^5})=\frac{32}{243}[/tex]
