Suppose that the number of asbestos particles in a sample of 1 squared centimeter of dust is a Poisson random variable with a mean of 1000. What is the probability that 10 squared centimeters of dust contains more than 10040 particles?

Respuesta :

Answer:

p=0.3446

Step-by-step explanation:

-Let Y be the random variable with parameter [tex]\lambda=1000[/tex].

-The probability mass function is given as:

[tex]f(y)=\frac{e^{-\lambda T}(\lambda T)}{y!}, \ y\geq 0[/tex]

We set T=10, and calculate the probability as

[tex]P(Y>10040)=1-P(Y\leq 10040)\\\\=1-P[\frac{Y-10000}{\sqrt{10000}}\leq \frac{10040-10000}{100}]\\\\=1-P(Y\leq 0.4)\\\\=1-0.65542\\\\=0.34458[/tex]

Hence, the probability that 10 squared centimeters of dust contains more than 10040 particles is 0.3446